AI & ML
Sharp detection and triangle likelihood limits for quadratic spherical kernel graphs
arXiv stat.TH0 views
arXiv:2610.24759v1 Announce Type: cross Abstract: We study whether quadratic spherical geometry can be detected from a single observed graph. Latent positions are independent and uniform on $\mathbb S^{d-1}$; conditional on them, edges are independent with connection probability $K_{d,\beta}(t)=[1+\beta(dt^2-1)/(d-1)]/2$, where $0<|\beta|\le1$. We test this model against $G(n,1/2)$. Writing $N=(d-1)(d+2)/2$ for the degree-two harmonic multiplicity, we prove that the total variation distance tends to one when $N\ll n^{3/4}|\beta|^{3/2}$ and to zero when $N\gg n^{3/4}|\beta|^{3/2}$. At criticality, if $N\to\infty$ and $\Delta_n=\sqrt{\binom n3}\,|\beta|^3/N^2\to\Delta\in(0,\infty)$, the signed triangle captures all asymptotic testing information and the total variation distance tends to $2\Phi(\Delta/2)-1$, where $\Phi$ is the standard normal distribution function. Polynomial finite-sample error bounds hold under polynomial signal scaling. The proof controls the likelihood of the dependent quadratic feature law through spectral recursions, covariance truncation and interpolation from a symmetric prior.
Source:https://arxiv.org/abs/2610.24759PreviousThe Segal-Bargmann Transform in Neural Partial Differential EquationsNextA Tensor Critical Threshold in Cubic Spherical Kernel Graphs
Related posts
Cloudflare DNS Zone Builder cuts peak memory 85% and halves build delay
0dev.to News
O dia em que a cliente pediu desconto num bolo de pistache (e pagou R$ 30 num cafe)
0dev.to Design
O telefone tocou as 19h: Por que cancelam seu contrato primeiro na crise?
0dev.to Design
Which Cursor model is best for everyday work?
0dev.to Productivity
Is AI going to get cheaper or more expensive?
0dev.to Machine Learning
Điểm tin Trí tuệ Nhân tạo & Mô hình Ngôn ngữ lớn (LLMs) tại Việt Nam (03/11/2026)
0dev.to Machine Learning